Question

A a particle starting from rest undergoes acceleration given by a=|t-2| m/s^2 where t is time in sec. Find velocity of particle after 4 sec. is:-


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Answer 1

Answer:

The equation for acceleration of the particle  is a=(t-2)/t (obtained assuming a linear variation as the deceleration is uniform and subsequently satisfying the boundary conditions ).

Integrate it to find the velocity as a function of time and put in the required value to get the particular solution. The answer should come out to be v= 3m/s.

Answer 2

Answer:

u=0

t=4sec

a=21m/s2

v=?

v=u+at

v= 0+ 84

v= 84m/s

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