Question

A
A projectile is given an initial velocity 3i + 4 j m/sec. Its maximum height is
(A) 0.8 m
(B) 0.4 m
(C) 0.45 m
(D) 8 m​

Answer 1

Answer:

Velocity of projectile  v=3i^+10j^   m/s

Speed of projectile  u=∣v∣=102+32=109   m/s

Angle of projectile  tanθ=310

⟹  sinθ=10910  and  cosθ=1093

Maximum height attained   H=2gu2sin2θ

∴    H=2(10)109×109100=5m

Horizontal range   R=gu2sin2θ=g2u2sinθcosθ

⟹   R=102(109)×109