Chemistry, asked by ghoshsupriya656, 9 months ago

a) a reaction of first order in A and second order in B
1. write differential rate equation
2. how is rate affected when concentration of B is tripled? ​

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Answered by Anonymous
2

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Answered by aditirathorejnv06
1

1,] Rate (r) = - d[R]/dt = k[A][B]^2 -------(i)

2,] when we increase the concentration of B triple then the rate is -:

(r') = k[A][3B]^2 ------------(ii)

(r')/(r) = k[A][3B]^2 / k[A][B]^2

r' = 9r

The reac^n rate will increase 9 time ...

I hope its helpful for u ........!!!

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