A
À sphere of mass 2kg and the
radius
5 cm is rotating at
the rate of
3oo rpm Calculate the torque required
to stop in
6.28 revolutions. Moment
of Inertia of the sphere about any
diameter 2/5 MR²
Answers
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Answer:
=2kg,R=5cm=5×10
−2
m,
ω
0
=300rev/min=
60
300×2π
=10πrad/s
θ=2πrev=2π×2 pi=4π
2
rad
α=?ω=0
α=
2θ
ω
2
−ω
0
2
=−
2×4π
2
100π
2
=−
2
25
rad/s
2
τ=Iα
=
5
2
MR
2
α=
5
2
×2×(5×10
−2
)
2
×
2
25
=2.5×10
−2
Nm
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