Question

a) a² + 9a + 8
(e) c2 – 9c + 20
(e) F2 +6f - 16​

Answer 1

Answer:

a) a²+9a+20

ans. = a²+5a+4a+20

= a(a+5)+4(a+5)

= (a+4)(a+5)

b) c²-9c+20

ans. = c²-4c-5c+20

=c(c-4)-5(c-4)

= (c-4)(c-5)

c) f²+6f-16

ans. = f²+8f-2f-16

= f(f+8)+2(f-8)

= (f+2)(f-8)