Math, asked by aussiekaurmtmihtm18, 8 months ago

e+e+e=15 e+c=8 c+e+b=10 b+c×j=

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Answered by ankursarkar63109
16

Answer:

e +e+e=15

e=5

e+c=8

C=3

C+e+b=10

3+5+b=10

b=2

Now,

B+C×J

=2+3×10 [Alphabetically j=10 ]

=32

Answered by qwmillwall
0

The answer is 32.

Given:

E + E + E = 15

E + C = 8

C + E + B = 10

To Find:

B + C × J = ?

Solution:

Here, we see that the alphabet is assigned some numerical value.

The values are A=1, B=2, C=3, D=4, E=5, and so on.

These numerical values satisfy the given equations.

⇒ E + E + E = 15

⇒ 5 + 5 +5 = 15

Similarly, we can calculate the value for B + C x J

B has value 2, C = 3 and J = 10

⇒ B + C x J

⇒ 2 + 3 x 10

⇒ 2 + 30

⇒ 32        (Ans.)

Therefore the required answer is 32.

#SPJ2

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