e+e+e=15 e+c=8 c+e+b=10 b+c×j=
Attachments:
Answers
Answered by
16
Answer:
e +e+e=15
e=5
e+c=8
C=3
C+e+b=10
3+5+b=10
b=2
Now,
B+C×J
=2+3×10 [Alphabetically j=10 ]
=32
Answered by
0
The answer is 32.
Given:
E + E + E = 15
E + C = 8
C + E + B = 10
To Find:
B + C × J = ?
Solution:
Here, we see that the alphabet is assigned some numerical value.
The values are A=1, B=2, C=3, D=4, E=5, and so on.
These numerical values satisfy the given equations.
⇒ E + E + E = 15
⇒ 5 + 5 +5 = 15
Similarly, we can calculate the value for B + C x J
B has value 2, C = 3 and J = 10
⇒ B + C x J
⇒ 2 + 3 x 10
⇒ 2 + 30
⇒ 32 (Ans.)
Therefore the required answer is 32.
#SPJ2
Similar questions