a ∆ABC, P,Q,R are the midpoints of AB, BC and AC respectively. If AB=10 cm, BC=8 cm and AC= 12 cm. The perimeter of ∆PQR will be *
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The midpoint theorem states that “The line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to its third side and is also half of the length of the third side.”
According to above theorem
PQ=6cm
QR=5cm
RP=4cm
∴ Perimeter of ∆PQR
PQ+QR+RP= 6+5+4
Perimeter of ∆ PQR
=>15cm
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