Question

A age is five times as that of b , ten year later ,a age will be thrice that of b, find a age.

Answer 1

Let the age of B be x
A = 5x
B = x

Ten's years later

A = 5x + 10
B = x + 10

According to the question

5x + 10 = 3(x + 10)
5x + 10 = 3x + 30
2x = 20
x = 10

A's age = 5x = 5*10 = 50years
B's age = 10years

Answer 2

Answer:

Solution : Present age of B = x years

Present age of A = 5x years

According to question

5x + 10 =3(X+ 10)

5x + 10 = 3x + 30

5x – 3x = 30 – 10

2x = 20

X = 20/2

X = 10

Hence present age of B = 10 years

And present age of A =5x10 = 50 years