Math, asked by manojbhise91661, 1 year ago

A alone can complete a work in 16 days and b alone in 12 days starting with a they work alternate days

Answers

Answered by mdkhan7393
0

14 5/8

Step-by-step explanation:

A=16days & B=12days

LCM of 16 & 12 is 48

Now, 16/48=3 ,12/48=4

A's one day work 3 unit & B's one day work 4 unit in 2 days 7 unit of work completed

In 1=(1×2)days(2×7)=14 unit of work completed

In (1×3)=3days(7×3)=21days unit completed .............

In (2×7)= 14days (7×7) =49 unit completed remaining 5 unit work completed in 5/8 days

Hence work is completed in 14 5/8

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