A alone can complete a work in 16 days B alone in 12 days. starting with A, they work on alternate days. the total work completed in how many days
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let the work be completed in x days
A does 1/16 work in a day
B does 1/12 work in a day
So A has to work x/16 of work
B has to work x/12 of work
As they are working alternate day they would produce twice the work in x days
⇒x/16+x/12=2
⇒7x=96
x=13.7=14
The work would be complete in 14 days.
A does 1/16 work in a day
B does 1/12 work in a day
So A has to work x/16 of work
B has to work x/12 of work
As they are working alternate day they would produce twice the work in x days
⇒x/16+x/12=2
⇒7x=96
x=13.7=14
The work would be complete in 14 days.
dar:
there is no option. the option are
Answered by
1
An easy way to do this problem is
Let W be the work.
Then
A x 16 = W
B x !2 = W
Total work to be completed is W
Since A and B are working in alternate days , only half of the work they do alone is required when they work together to complete the task.
Hence,
A + B = W
2
16 + 12 = 28 = 14
2 2
So the days taken to complete the whole work by A and B is 14 days.
Let W be the work.
Then
A x 16 = W
B x !2 = W
Total work to be completed is W
Since A and B are working in alternate days , only half of the work they do alone is required when they work together to complete the task.
Hence,
A + B = W
2
16 + 12 = 28 = 14
2 2
So the days taken to complete the whole work by A and B is 14 days.
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