How is 3x-y=8 and x+2y=5 solved by combination (addition)?????
jagwantsandhu:
did i answer it right
Answers
Answered by
0
First, multiply the first equation by 2.
That turns the first equation into:
6x - 2y = 18
That way it can easily be added to the second equation:
6x - 2y = 16
x + 2y = 5
---------------
7x = 21
==========
As you can see, the y disappeared, which was the objective of this operation.
Now the equations can be solved easily:
7x = 21
x = 3
Insert x=3 in the original equation:
3*3 - y = 8
9 - y = 8
9 = 8 + y
y = 1
So the result is:
x = 3
y = 1
That turns the first equation into:
6x - 2y = 18
That way it can easily be added to the second equation:
6x - 2y = 16
x + 2y = 5
---------------
7x = 21
==========
As you can see, the y disappeared, which was the objective of this operation.
Now the equations can be solved easily:
7x = 21
x = 3
Insert x=3 in the original equation:
3*3 - y = 8
9 - y = 8
9 = 8 + y
y = 1
So the result is:
x = 3
y = 1
Answered by
0
multiply by 2 =
6x-2y=18
now add
6x - 2y = 16 x + 2y = 5
---------------
7x = 21
==========
y is gone
now it is easy
7x=21
x=21 divide by 7
x=3
now insert it
3*3-y=8
9-y=8
9=8+y
y=1
So the result is: x = 3 y = 1
6x-2y=18
now add
6x - 2y = 16 x + 2y = 5
---------------
7x = 21
==========
y is gone
now it is easy
7x=21
x=21 divide by 7
x=3
now insert it
3*3-y=8
9-y=8
9=8+y
y=1
So the result is: x = 3 y = 1
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