A alone can do 1/4th of the work in 2 days. b alone can do 2/3th of the work in 4 days. if all the three work together, they can complete it in 3 days so what part of the work will be completed by c in 2 days?
Answers
Answered by
49
A alone can do 1/4th of the work in 2 days so their one day work will be 1/8th of the total work. alone can do two third of the work in 4 days, so B's one day work will be one sixth of the total work. Since A, B and C together can complete the work in 3 days, their one day work will be one third of the total work.
Let C's one day work be x.
A.T.Q.,
1/8 + 1/6 + x = 1/3
x = 1/24
Therefore C will complete 1/12th of the work in 2 days.
Let C's one day work be x.
A.T.Q.,
1/8 + 1/6 + x = 1/3
x = 1/24
Therefore C will complete 1/12th of the work in 2 days.
Answered by
11
Answer:
A =8
B=6
A+B+C=3
LCM(8,6,3)=total work=24U
Now efficiency of ...
A=3 U
B=4U
A+B+C=8U
therefore eff. of C=8-(3+4)= 1U
So C performs 1 Unit work per day.
In 2 day he will perform 2U.
Total work is 24U
So part done by C=2/24=1/12
Step-by-step explanation:
Similar questions