Question

A alone can finish a work in 40 days and B in 60 days.initially A Alone start the work.after 20 days,he left the work.in how many days B alone can finish the remaining work?

Answer 1

Answer:

57 days

Step-by-step explanation:

above is your solution..............

Answer 2

Answer:

B alone can finish the remaining work in 30 days .

Step-by-step explanation:

A can complete work in days = 40

A's 1 day work = $\frac{1}{40}$

B can complete work in 60 days.

B's 1 day work = $\frac{1}{60}$

A did work for 20 days

A did part of work in 20 days = $\frac{20}{40}=\frac{1}{2}$

Remaining work = $1-\frac{1}{2}= \frac{1}{2}$

B can complete work in days = 60

So, B can compete remaining work in days = $60 \times \frac{1}{2} = 30$

Hence B alone can finish the remaining work in 30 days .