Question

(a) An electric iron is rated at 230 V, 750 W. Calculate (i) the maximum current, and (ii) the number of units of electricity it would use in 30 minutes.
(b) Which of the following fuse ratings would be suitable for this electric iron?
1 A, 3 A, 5 A, 13 A

Answer 1

Explanation:

According to the question, an electric iron is rated at 230 V of voltage and 750 W of power.

Maximum current, I = ?

As we know, P = VI

So,   $I = \frac{P}{V} = \frac{750W}{230} V = 3.26 A$

The number of units of electricity it would use in 30 minutes is,

i.e., $E = P\times t$

$= 750 W\times 30 mins = 22,500 Wm$

Converting into KWh , we have, E ≅ 0.375 KWh

(b) Out of the following fuse ratings, 5 A would be suitable for this electric iron.

You can get all the answers of Chapter 2 in the link below:

https://brainly.in/question/14961525

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