Question

Calculate the number of aluminium ions present in 0.051 g of aluminium oxide (Al2O3). (Atomic masses Al = 27 u; O = 16 u)

Answer 1

Answer:

Explanation:

No. of aluminium ions (Al3+) present in the same as the no. of Al atoms.

Answer 2

Answer:3.011*10^26 no.of aluminium ions.

Explanation: 27*2+16*3=54+48

= 102u

= 102g

No.of ions = mole * avogadro number

= 0.051/102 * 6.022*10^23

= 0.0005 * 6.022*10^23

= 0.003011 * 10^23

= 3.011*10^26 no. Of aluminum ions.