a. An electric iron of 1100 W is operated for 2 hrs daily. What will be the electrical
consumption expenses for that in the month of June? (The electric company
charges Rs 5 per unit of energy).
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Explanation:
Energy = 1100W = 1.1Kw
Energy=power*time=1.1(kw)*2(hr)=2.2kwh
Energy used in a day=2.2 unit
Energy used in 30 days= 2.2×30unit = 66unit
Total cost=66×5=330 rs
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