a) An object is placed at a distance of 30cm tom a concave lens of focal length
15cn List lour characteristics nature position size) of the image formed by the lens
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Answer:
concave lens produces a virtual, erect diminished image.
Using Real Is Positive RIP Convention, u=30 and f=-15
1/u+1/v=1/f
1/30+1/v=−1/15
1/v=−1/15−1/30=−3/30=−1/10
v=−10M=v/u=−1/3
So image is erect, virtual, 1/3 size of object, and 10 cm from the lens, (between lens and object)
Answered by
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Answer:
u=-30cm f= -15cm
1/f=1/v-1/u
1/v=1/f+1/u
on substituting v=-10cm
m=v/u
m=-10/-30
m=1/3=.33
so the magnification is positive so it is a virtual erect image .
is less than 1 so the image is diminished .
and v is negative so the image is formed on the same side of the lens.
Explanation:
hope it helps
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