Question

a) An object is placed at a distance of 30cm tom a concave lens of focal length
15cn List lour characteristics nature position size) of the image formed by the lens​

Answer 1

Answer:

concave lens produces a virtual, erect diminished image.

Using Real Is Positive RIP Convention, u=30 and f=-15

1/u+1/v=1/f

1/30+1/v=−1/15

1/v=−1/15−1/30=−3/30=−1/10

v=−10M=v/u=−1/3

So image is erect, virtual, 1/3 size of object, and 10 cm from the lens, (between lens and object)

Answer 2

Answer:

u=-30cm   f= -15cm  

1/f=1/v-1/u

1/v=1/f+1/u

on substituting  v=-10cm

m=v/u

m=-10/-30

m=1/3=.33

so the magnification is positive so it is a virtual erect image .

is less  than 1 so the image is  diminished .

and v is negative so the image is formed on the same side of the lens.

Explanation:

hope it helps