a)An object thrown vertically upward rises to a height of 10m. Calculate,
i) the velocity with which the object was thrown upward.
ii) the time taken by the object to reach the highest point.
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Answer:
height (h)=10m
1)velocity with which it is thrown up =v=√2gh
=√2×10×9.8
=√19.6
=1.4m/s
2)time taken to reach highest point=time of ascent=v/g
= 1.4/9.8
=1/7 sec
Explanation:
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