Question

A and are dependent
51.
A card is drown from each of two well-shuffled packs of cards. The probability that a
least one of them is an ace is
25
d) none
13​

Answer 1

Answer:

there are three case made for selection :

• Ace selected from first pack and selected other card from second pack
• any card but not ace selected from first and ace selected from second
• select Ace from both pack

case 1 = 4/52 × 48/52 = 192/2704

case 2 = 48/52 × 4/52 = 192/2704

caee 3 = 4/52 × 4/52 = 16/52

Answer of probablity= 192+192+16/2704

= 400/2704

= 25/169

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