Question

A and B are among 5 members of a group. They are standing for a group photo. In how many ways they can stand such that B is always left of A?

Answer 1

Answer:

24 ways

Step-by-step explanation:

Total number of members = 5

Let they are A, B, C, D, E

Since B is always left of A

Therefore if we take them as one entity, there will be total 4 people to be arranged

$\boxed{AB}, C,D,E$

They can be arranged in $4!$ ways

$4!=24$

Thus there are 24 ways they can stand that B is always left of A

Hope this helps.

Answer 2

Answer:

Total members is 5

Out of these 5 members (2 persons) means A and B never change their position because B is always left of A.

Only three members can change their position so that,

Take nPr formula

n=5, r=3

5P3= 60.

Answer is 60..

Step-by-step explanation: