Question

A and B are friend and their ages differ by 2 years father he is twice as old as a and b is twice as old as his sister she is the age of D and for 40 years is find the age of a and b​

Answer 1

Step-by-step explanation:

let the age of A = x

age of B = x+2

since, A's father D is twice as old as A

So, age of D = 2×x = 2x

and since B is twice as old as his sister

So, age of C = age of B / 2 = (x+2)/2

according to the question,

The ages of D and C differ by 40yrs.

it means,

age of D - age of C = 40

=> 2x - [(x+2)/2] = 40

=> 2x - (x+2)/2 = 40

=> 4x/2 - (x+2)/2 = 40

=> (4x - x + 2)/2 = 40

=> 3x+2/2 = 40

=> 3x + 2 = 40 × 2

=> 3x = 80 - 2

=> x = 78/3

= 26

So, age of A = x = 26yr.s

age of B = x + 2 = 26 + 2 = 28yr.s