A and B are friends and their ages
differ by 2 years A's father D is twice
as old as A and B is twice as old as his
sister c the
age
of D and C differ by 40
years. find the ages of
A and B
A
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Let the ages of A and B be x and y years respectively. Then,
x−y=±2 [Given]
D's age =2x years and, C's age =y/2 years
Clearly, D is older than C
2x− y/2 =40⇒4x−y=80
Thus, we have the following two systems of linear equations
x−y=2 .(i)
and, 4x−y=80 (ii)
or
x−y=−2 (iii)
and, 4x−y=80 ..(iv)
Substracting equation (i) from equation (ii), we get
3x=78⇒x=26Putting x=26 in equation (i), we get y=24
or
Substracting equation (iv) from equation (iii), we get
−3x=−82⇒x=82/3 = 27⅓
Putting x= 82/3 in equation (iii), we get
y= 82/3 +2=88/3 =29 ⅓
Hence, A's age =26 years and B's age =24 years
or
A's age =27 ⅓ years and B's age =29 ⅓ years.
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