A and B are friends and their ages differ by a year. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C differ by 40 years. Find the ages of A and B.
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Answer:
27 years and 28 years
Question can pl corrected like
A and B are friends and their ages differ by 1 years. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C differ by 40 years. Find the ages of A and B.
Step-by-step explanation:
Let ages of A and B are x and y
A and B are friends and their ages differ by 1 years
so y-x=1-------------------(1)
A's father D is twice as old as A
D's age=2x
B is twice as old as his sister C
C's age=1/2*y=y/2
D's age-C's age=40
2x-y/2=40
4x-y=80-----------------------(2)
Adding (1) from (2)
3x=81
x=81/3=27
y=x+1
=27+1=28
so their ages are
27 years and 28 years
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