Math, asked by GINAC, 10 months ago

A and B are friends and their ages differ by a year. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C differ by 40 years. Find the ages of A and B.​


GINAC: hello?

Answers

Answered by Anonymous
3

Answer:

27 years and 28 years

Question can pl corrected like

A and B are friends and their ages differ by 1 years. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C differ by 40 years. Find the ages of A and B.​

Step-by-step explanation:

Let ages of A and B are x and y

A and B are friends and their ages differ by 1 years

so y-x=1-------------------(1)

A's father D is twice as old as A

D's age=2x

B is twice as old as his sister C

C's age=1/2*y=y/2

D's age-C's age=40

2x-y/2=40

4x-y=80-----------------------(2)

Adding (1) from (2)

3x=81

x=81/3=27

y=x+1

=27+1=28

so their ages are

27 years and 28 years


GINAC: there ages are 27 and 28
GINAC: Difference between age of a and b is 1
Anonymous: ok i edited
Anonymous: ok
Similar questions