A and B are frnds. ignoring the leap year, find the probability that both frnds will have: 1.different birthdays? 2. same birthday? plz answer the question the correct one will be mark as brainliest.
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We know that number of days in a year = 365.
Since there are two birthdays, therefore the sample space will be
n(S) = 365 * 365.
(1) Let E be the event that A and B have different birthdays.
A can have the birthday on any of the 365 days and B have can birthday on any of the remaining 364 days.
n(A) = 365 * 364
Therefore the required probability P(A) = n(A)/n(S)
= 365 * 364/365 * 365
= 364/365.
(2) Let E1 be the event that A and B have the same birthday.
n(E1) = 1 - P(A)
= 1 - 364/365
= 1/365.
Hope this helps! ------------- Good Luck.
Since there are two birthdays, therefore the sample space will be
n(S) = 365 * 365.
(1) Let E be the event that A and B have different birthdays.
A can have the birthday on any of the 365 days and B have can birthday on any of the remaining 364 days.
n(A) = 365 * 364
Therefore the required probability P(A) = n(A)/n(S)
= 365 * 364/365 * 365
= 364/365.
(2) Let E1 be the event that A and B have the same birthday.
n(E1) = 1 - P(A)
= 1 - 364/365
= 1/365.
Hope this helps! ------------- Good Luck.
31shivani:
thnk u so much
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