Question

A and B are in the ratio 3:2. after 6 year, the ratio of thir ages is 11:8. find their present ages​

Answer 1

Answer:

age of A=27

age of B=18

Step-by-step explanation:

Let x be any variable.

Then,

A = 3x

B = 2x

After 6 years

Age of A = 3x+6

Age of B = 2x+6

Ratio of ages= (3x+6)/(2x+6)

Ratio given = 11/8

Now

(3x+6)/(2x+6)=11/8

By cross multiplication

LHS=(3x+6)8= 24x+48

RHS=11(2x+6)=22x+66

24x+48=22x+66

subtracting 22x from both sides

24x+48-22x=22x+66-22x

Simplifying

2x+48=66

Subtracting 48 from both sides

2x+48-48=66-48

Simplifying

2x=18

Dividing both sides by 2

2x/2=18/2

Simplifying

x=9

Now,

Present age of A= 3x = 3x9 = 27

Present age of B= 2x = 2x9 = 18

Answer 2

Step-by-step explanation:

lets ,a=3x

B=2x

After 6 year they will be

3x + 6=11

2x + 6=8

8(3x + 6)=11(2x +6)

=24x + 48=22x +66

=24x-22x=66-48

=2x= 18

=x =18

2

= x =9

Than A=3x

= 3×9

=27

B=2x

=2×9

=18

SO,

The present age is 27& 18 respectively

I hope its help you.