A and b are length of right angle triangle whose hypotenuse are 10 and area 20
Answers
Answered by
0
area of a 90° triangle =1/2 ×P×B
40=P×B
H=10
P^2 +B^2=H^2
100=(P+B)^2-2PB
100+80=(P+B)^2 (2PB=80)
13.41=P+B
P=4.48
B=8.93
40=P×B
H=10
P^2 +B^2=H^2
100=(P+B)^2-2PB
100+80=(P+B)^2 (2PB=80)
13.41=P+B
P=4.48
B=8.93
Similar questions
Chemistry,
7 months ago
Political Science,
1 year ago
Physics,
1 year ago
Environmental Sciences,
1 year ago
Science,
1 year ago