Question

A and B are standing on ground 50 meters apart. The angles of elevation for these two to the top of a tree are 60° and 30°. What is height of the tree?​

Answer 1

Step-by-step explanation:

here your answer in the attachment

...hope helpful tips

Answer 2

In ∆PBQ, tan 60° = PQ/BQ

Therefore, BQ = PQ/√3

In ∆PAQ, tan 30° = PQ/AQ

Therefore, 1/√3 = PQ/50 + BQ

PQ = 50 + BQ/√3

= 50 + PQ/√3 /√3

= 50√3 + PQ / √3 × √3

Therefore, 3PQ = 50√3 + PQ

Therefore, PQ = 25√3m = Height of the tree.

Thanks for your question.

Hope my answer helps you.