A and B are the only two outcomes of an event . probability of P(A) is 0.72 , then what will be the probability of B
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P(A)+P(B)=1
0.72+P(B)=1
P(B)=1-0.72
P(B)=0.28
0.72+P(B)=1
P(B)=1-0.72
P(B)=0.28
shaikhsalena:
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The probability of B will be 0.28.
It is given that,
A and B are the only two outcomes of an event.
If P(A) is the probability of event A and P(B) is the probability of event B, then, the total probability of these two events will be equal to 1.
P(A) + P(B) = 1
Now P(B) = 0.72
We will put this value of P(B) and find the probability of A.
P(A) = 1 - P(B)
P(A) = 1 - 0.72
P(A) = 0.28
Therefore, the probability of B will be 0.28
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