A and B are two alloys which were made by mixing iron and copper in the ratio of 3:5 and 5:9 respectively.If 60 grams of alloy A and X grams of alloy B are melted and mixed to form another alloy C what is the value of X if the ratio of iron and copper in the new alloy is 35:61 ?
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Given:
Two alloys = A and B
Ratio of Iron = 3:5
Ratio of Copper = 5:9
Weight of alloy A = 60gms
Weight of alloy B = x gms
To Find:
Value of X if ratio of iron and copper in the new alloy is 35:61
Solution:
In x gms of alloy B
Iron = 5 × x/14
Copper = 9 × x/14
In 60gms of alloy A
Iron = 60 × 3/8
= 45/2
Copper = 60 × 5/8
= 75/2
According to question -
45/2 + 5x/14 / 75/2 + 9x/14
= 35/61
= x = 84
Answer : The value of x is 84 grams.
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