Question

Find all the other zeroes of the polynomial 2x^3+3x^2-11x-6 if one of its zeroes is -3
Plz answer fast
It should be correct
Help plz

Answer 1

★ Answer :

Refer to the attachment firstly

Now, we will factorise 2x² - 3x - 2.

→ 2x² - 3x - 2 = 0

→ 2x² - 4x + x - 2 = 0

→ 2x(x - 2) + 1(x - 2) = 0

→ (2x + 1)(x - 2) = 0

→ 2x - 1 = 0

→ 2x = 1

→x = 1/2

Or

→ x - 2 = 0

→ x = 2

$\rule{200}{1}$

Answer 2

SoluTion:

Given Polynomial :

• 2x³ + 3x² + 11x - 6

One zero :

• -3

We have to divide, given Polynomial by (x + 3).

[ Refer to the attachment for division ]

After division, we get quotient as (2x² - 3x - 2)

Now, by splitting middle term,

→ 2x² - 4x + x - 2

→ 2x (x - 2) + 1 (x - 2)

→ (2x + 1) (x - 2)

For finding other zeroes, equate it to zero.

→ (2x + 1) = 0 and (x - 2) = 0

→ 2x = -1 → x = $\sf{\dfrac{-1}{2}}$ and x = 2

Hence, all the zeroes of given Polynomial are 2, -3 and $\bold{\dfrac{-1}{2}}$