A and b are two different chemical species undergoing first order decomposition with half lives to 5 sec and 7.5 second. If initial concentration of a and b are in the ratio 3:2 calculate
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A’s Half life = 2 years {let}
B’s Half life = 3 years {let}
After 3 half lives =>
Concentration of A = A/8 and time taken = 2*3 = 6 years.
Bj will be B/2 at 3 years and after 6 years it would be B/.
Ratio = (A/8)/(B/4) = > 3/4
Hope it will help uu
B’s Half life = 3 years {let}
After 3 half lives =>
Concentration of A = A/8 and time taken = 2*3 = 6 years.
Bj will be B/2 at 3 years and after 6 years it would be B/.
Ratio = (A/8)/(B/4) = > 3/4
Hope it will help uu
Answered by
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Answer:
Explanation:
A’s Half life = 2 years {let}
B’s Half life = 3 years {let}
After 3 half lives =>
Concentration of A = A/8 and time taken = 2*3 = 6 years.
B will be B/2 at 3 years and after 6 years it would be B/4.
Ratio = (A/8)/(B/4) = > 3/4
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