Physics, asked by Durrr, 1 year ago

A and B are two Hills at a distance 480 metre apart a person standing between The Hills Club season and hairs to expose and the and of one second and 2 second the velocity of sound in air is​

Answers

Answered by knjroopa
21

Explanation:

Given A and B are two Hills at a distance 480 metre apart. A person standing between the Hills Claps his hands and hears season and hears two echoes at the and of one second and 2 seconds respectively. The velocity of sound in air is

  • Let distance of person from hill A be x metre, then from hill B is (480 – x) m
  • Therefore x / 480 – x = time 1 / time 2
  •                                = 1/2  
  •               So x = 160 m
  • Time taken for the echo to travel 160 m is given by 1/2 = 0.5 s
  • Velocity = distance / time
  •             = 160 / 0.5

           = 320 m/s

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