A and B are two mutually exclusive events if P(A) = 0.5 and P(B’) =0.6.Find P(AUB)
het:
is dat P(B)?
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Since A and B are mutually exclusive P(A∩B)=0
So,
P(A∪B)=P(A)+P(B)-P(A∩B)
=0.5+0.6-0
=1.1
So,
P(A∪B)=P(A)+P(B)-P(A∩B)
=0.5+0.6-0
=1.1
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