A and B are two objects. what happens to the force between two objects if
1) the mass of "A" is doubled.
2) the distance between "A" and "B" is doubled
3) the masses of both "A" and "B" are
doubled.
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Answers
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Given;
•There're two objects A and B
To Find;
1) When the mass of ''A'' is doubled,
According to the Universal Law of Gravitation,
F = G m1 m2 / r^2. ..... (1)
considering mass of A be m1
doulbing it = m1^2.
F' = G m1^2 m2 / r^2. ......(2)
dividing both equations
F' / F = (G m1^2 m2 / r^2) × (r^2 / G m1 m2)
F' / F = m1
therefore, F' = m1 × F
So, if mass of A is doubled then the force would increase.
2) If the distance is doubled then the force would reduce.
F" = G m1 m2 / r^4
3) If the masses of both A and B is doubled then the force would increase and it would be equal to the product of two masses and the force between them.
F"' = G m1^2 m2^2 / r^2
F"' = m1 m2 F
if the masses of both is doubled then the force between will be four times the initial force.
•There're two objects A and B
To Find;
1) When the mass of ''A'' is doubled,
According to the Universal Law of Gravitation,
F = G m1 m2 / r^2. ..... (1)
considering mass of A be m1
doulbing it = m1^2.
F' = G m1^2 m2 / r^2. ......(2)
dividing both equations
F' / F = (G m1^2 m2 / r^2) × (r^2 / G m1 m2)
F' / F = m1
therefore, F' = m1 × F
So, if mass of A is doubled then the force would increase.
2) If the distance is doubled then the force would reduce.
F" = G m1 m2 / r^4
3) If the masses of both A and B is doubled then the force would increase and it would be equal to the product of two masses and the force between them.
F"' = G m1^2 m2^2 / r^2
F"' = m1 m2 F
if the masses of both is doubled then the force between will be four times the initial force.
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