Math, asked by samir252, 1 year ago

what is the dx value 2x+2y-4=0; 6x+9y+3=0​

Answers

Answered by harshkunar
1

First equation 3x +2y = 17

Multiple to each side by negitve 2.

-6x -4y = -34 ---> (1)

Second equation 2x +5y = 26

Multiple to each side by 3.

6x +15y = 78 ---> (2)

To eliminate the x value add the (1)&(2).

-6x -4y = -34

6x +15y = 78

________________

11y = 44

Divide to each side by 11.

y = 4

Substitute the y value in (2).

6x +60 = 78

Subtract 60 from each side.

6x = 18

Divide to each side by 6.

x = 3

Solution x = 3, y = 4.

Answered by mushu1234
3

2(1)+2y-4=0

2+2y-4=0

2y-2=0

2y=2

y=2/2

y=1

now.....

6x+9y+3=0

6x+9(2)+3=0

6x+18+3=0

6x+21=0

6x=-21

x=-21/6

x=-7/3

hope it will help you....


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