# A and B are two pipes connected to a tank. A is the filler pipe and B is the ejector. The capacity of the tank is 6000L.The ejector pipe can eject water at the rate 4L/min higher than the filler pipe. The filler pipe can fill the tank 5 min later than the ejector pipe can eject. Find the flow rate of the ejector pipe in L/min(approx.).

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**Step-by-step explanation:**

### Given : ejector pipe can eject water at the rate 4L/min higher than the filler pipe . The filler pipe can fill the tank 5 min later than the ejector pipe can eject

### To find : flow rate of the ejector pipe in L/min(approx.).

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ejector pipe flow rate = E L/Min

Filler Pipe flow rate = E - 4 L/Min

Capacity of Tank = 6000 L

Time Taken by Ejector pipe = 6000/E Min

Time Taken by filler pipe = 6000/(E - 4) Min

The filler pipe can fill the tank 5 min later than the ejector pipe can eject.

=> 6000/(E - 4) = 6000/E + 5

=> 6000E = 6000(E - 4) + 5E(E - 4)

=> 6000E = 6000E - 24000 + 5(E² - 4E)

=> 5(E² - 4E) - 24000 = 0

=> E² - 4E - 4800 = 0

=> E = (4 ± √(4² - 4*(-4800)) ) /2

=> E = 2 + √4801 ( ignoring - ve value)

=> E = 2 + 69.3

=> E = 71.3

flow rate of the ejector pipe = 71.3 L/min

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