A and b are two stations 390 km apart. A train starts from a at 10 am and travels towards b at 65 kmph. Another train starts from b at 11 am and travels towards a at 35 kmph. At what time do they meet?
Answers
Given :-----
- Distance b/w A and B stations = 390km.
- Speed of Train starts from A = 65km/h and it starts at 10am.
- Speed of Train starts from B = 35km/h and it starts at 11am.
To Find :------
- At what time they will meet ?
Solution :--------
Train starts From A at 10am , at speed of 65km/h and upto 11am , in 1 hour that travel and let reach at Point C .( see in diagram ) .
→ D = S × T
→ D = 65 × 1 = 65km .
now,
Distance left to be travelled = 390-65 = 325km ..
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Now, From C train travel at 65km/h and From B train travel at 35km/h , both at same time now, and let, they meet at Point D ...
Since ,
Both Trains are traveling Towards each other (opposite Direction ) .
So,
→ Usual Speed = 65+35 = 100km/h .
→ Distance to cover now = C to B = 325km .
→ Time = Distance / Speed .
→ Time = (325/100) = 13/4 = 3(1/4) = 3 Hours (60/4) = 3:15 = 3 hours 15 minutes ..
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Hence, Both Train will meet at
==>> 11:00 am + 3 : 15 = 14 : 15 = 2 : 15 pm .
So, Both Train will meet at 2:15PM...
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