A and B are two vectors given by A=-i+3j+2k amd B=i+j. then a vector pf magnitude 3 which is perpendicular to both A and B.?
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let the required vector is "C".
so, C = magnitude × direction
magnitude = 3
direction = unit vector perpendicular to both A and B.
= unit vector of (A × B)
= (A × B) / |A × B|
A × B = i (0 - 2 ) + j ( 2 - 0 ) + k ( -1 - 3 )
= -2 i + 2 j - 4 k
| A × B | = √( 4 + 4 + 8 ) = √16 = 4
hence,
C = 3 (A × B) / |A × B|
C = 3 × 2( -i + j -2k) / 4
C = (3/2) ( -i + j + 2k)....... answer.
or, C = (3/2) ( i - j - 2k)....... answer.
answer...
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