A and B begin to play each with Rs 60 .if they play till A's money is double'B's,what doe A win?
Answers
Answer:
0.9224 Ans
Step-by-step explanation:
A and B play a game in which the probability of A winning each game is 3/5. If they play 5 games, what is the probability that B will win at least one game?
Don’t let change and uncertainty hold you back.
Since probability of A winning each game is 3/5. Probability of B winning each game (p) is 2/5. If they play a number of games, in this case 5 - it boils down to Bernaullis trial.
Prob. of B winning atleast 1 game = P (B exactly 1 game) + P(B winning exactly 2 game)+ …..3…+…..4…+….5…game.
We know from beranaullis trial that, Probability of exactly k sucess in n trials, for p(success in each trial) =
nCkpk(1−p)n−k
therefore
=5C1(2/5)(3/5)4+5C2(2/5)2(3/5)3+5C3(2/5)3(3/5)2+5C4(2/5)4(3/5)1+5C5(2/5)5(3/5)0
=0.9224
Sorry for the long method, but had to finish what i started..
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