A and B can complete a certain job in 20 and 30 days respectively. They start the job together and work for 3 days .Then B Falls sick and unable to do work for 5 days during which A works alone.Then again B joins him and they complete the work together. In how many days was the work completed?
Answers
Answer: we can use LCM METHOD....
As A can complete the work in 30 day. Surely... B could complete the work in 20 days.
Step-by-step explanation:
Here, we are going to calculate LCM of 30 and 20.
The total unit of work= LCM(20,30) = 60 units
So, the number of unit work done by A = 60/30=2 units
And, the number of unit work done by B = 60/20=3 units
As per the given information, B leaves the work 5 days before the work is finished.
Therefore, A would be working alone for the last 5 days and the amount of work done by A during those days= 2*5= 10 units
Therefore, Remaining amount of work = 60-10 = 50 units
These 50 units of work is done by both A and B together.
Therefore, working together work done per day by A and B = 2+3 = 5 units
Therefore, to complete 50 units of work A and B together requires = 50/5 = 10 days
So the total number of days to finish the work = 10+5= 15 days.
Therefore ur answer is 15 dayss.....
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6 ddays is correct answet
Step-by-step explanation:
A's 10 days work = 10×3 units/ days = 30 units
So,(60−30)=30 units of work would have been done by A
and B both and it took time:
30(3+2)=6days
So, B worked for 6 days