A and b can complete a work in 15 days b and c can complete in 10 days and c in 12 days.Time taken by a b c to do the job
Answers
A+B B+C C
15 10 12
Total work done = LCM(15,10,12)= 60 units
4 6 5
Work done by A+B in 1 day = 4 units
Work done by B+C in 1 day = 6 units
Work done by C in 1 day = 5 units
Now if C = 5 and B+C = 6,
then B = 1 units and A = 3 units
Now, 1 day work of A+B+C = 5 + 1 + 3 = 9
Time taken for A+B+C to complete total work = 60/9
= 6 2/3 days