A and B can complete a work in 40 days, B and C in 60 days and A and C in 48 days. Who is the most efficient worker among A, B and C?
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A is the most efficient worker.
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60%(A+B)=C; 3A+3B=5C
40%(A+C)=B; 2A+2C=5B
6A+6B=10C and 10A+10C=25B
Adding and cancelling 10C
19B =16A; B=16A/19
2C=5(16A/19)-2A ;C =42A/19; C=21A/19
A+16A/19+21A/19=1/38
A(1+16/19+21/19) =1/38
A=(1/38)(19/56)=1/102
A will take 102 days
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