Math, asked by evapauly1557, 11 months ago

A and b can do a job together in 7 days. A is 1.75 times as efficient as b. The same job can be done by a alone is :

Answers

Answered by Anonymous
0
Ratio of work done by A and B = 7/4 : 1 = 7:4

(A+B)'s 1 day's work = 1/7 (Given in the problem)
Divide 1/7 in the ratio 7:4
A's 1 day's work = (1/7 * 7/11)= 1/11
Hence,A alone can finish the work in 11 days.

B's 1 day's work = (1/7 * 4/11)=4/77 = 1/19.25
Hence,B alone can finish the work in 19.25 days.
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