Question

A and b can do a peice of work in 6 days, a alone do same work in 18 days how many days b alone can do same work

Answer 1

Let b alone can do the work in x days
Then,
$\frac{18x}{18 + x} = 6 \\ 18x = 18 \times 6 + 6x \\ 12x = 18 \times 6 \\ x = \frac{18 \times 6}{12} = 9 \: days$