Question

A bag contains 6 blue balls and 3 green balls and a box contains 4 blue balls and 5 green balls.find the probability that a ball randomly selected from either of them is a blue ball?

Answer 1

probability of finding the blue ball=no of favourable out comes /total no of out comes
=>10/18=5/9

Answer 2

Answer:

The probability of selecting a blue ball from the bag is 2/3.

The probability of selecting one  blue ball from the box is 4/9.

Step-by-step explanation:

If the ball will be selected from Bag:-

The number of blue balls in the bag = 6

The number of green balls in the bag = 3

The total number of balls = 6 + 3 = 9

The probability of getting one blue ball $=\frac{6}{9} =\frac{2}{3}$

If the ball will be selected from the box:-

Number of blue balls in the box = 4

Number of green balls in the box = 5

The total number of balls in the box = 4 + 5 = 9

The probability of getting one blue ball from box $=\frac{4}{9}$

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