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A and B can do a piece of work in 12 days, B and C can do it in 15 days, C and A can do the same
piece of work in 20 days. How long would each of them take to complete the job? Also find how
long will whey take to complete the same job if they work together?
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Answer:
A+B = 12
B+C = 15
A+C = 20
LCM of (12,15,20) = 60
Efficiency is
A+B = 5
B+C = 4
A+C = 3
Total Efficiency
2(A+B+C) = 12
A+B+C = 6
Imvidual Efficiency
A = 6-4 = 2
B = 6-3 = 3
C = 6-5 = 1
Invidual time taken
A = 60/2 = 30 days
B = 60/3 = 20 days
C = 60/1 = 60 days
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