A and B can do a piece of work in 12 days, B and C in 15 days, C and A in 20 days. How long would A take separately to do the same work
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Step-by-step explanation:
A+B(1day′s)=121work
B+C(1day′s)=151work
A+C(1day′s)=201work
Adding all the above,
2(A+B+C)(1day′s)=121+151+201
=605+4+3=6012=51work
∴A+B+C(1day′s)=101work
∴C(1day′s)=(A+B+C)(1day′s)−(A+B)(aday′s)
=101−
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