A and B can do a piece of work in 12 days. B and C in 15. days C and a in 20 days. How many time will A alone take to finished the work ?
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A+B = 12
B+C = 15
A+C = 20
Lcm of (12,15,20) = 60
Efficiency is
A+B = 5
B+C = 4
A+C = 3
Total efficiency
2 (A+B+C) = 12
A+B+C = 6
Individual efficiency
A = 6 - 4 = 2
B = 6 - 3 = 3
C = 6 - 5 = 1
Individual time taken
A = 60/2 = 30 days
B =60/3 = 20 days
C = 60/1 = 60 days
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anand7836:
only A alone take to finished the work ?
30 days
Di..do u know Divya?
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0
Answer:
Step-by-step explanation:
(A+b)+(b+c)+(c+a)=12+15+20
2(a+b+c)=47
A+15=47/2. (B+C=15)
A=47/2-15/1
A=47-30/2
A=8.5
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