A and B can do a piece of work in 18 days B and C can do it in 24 days A and C can do it in 36 days. In how many days will A, B and C finish it working separately?
Answers
Step-by-step explanation:
A takes x days and B takes y days C takes z days
x + y = 18 -------(1)
y +z = 24
x + z = 36
x = 36 - z
y = 24 -z
Putting in eq(1)
36 - z + 24 -z = 18
42 = 2z
z = 21 days
x = 36 - 21
x = 15 days
y = 24 - 21
y = 3 days .
Answer:
16 days
Step-by-step explanation:
Work done by A and B in one day=1/18
Work done by B and C in one day=1/24
Work done by A nd C in one day=1/36
So, total work done if all of them work together is,
(work done by A and B in one day) +(work done by B and C in one day) +(work done by A and C in one day)=1/18+1/24+1/36
Or
2(work done by A, B and C in one day) =1/18+1/24+1/36
=(4+3+2)/72
=9/72
=1/8
Or
work done by A, B and C in one day
=1/2*1/8
=1/16
So, time taken by A, B and C to complete the work =1/(1/16)=16 days.