A and b can do a piece of work in 24 days ,b and c can do apiece of work in 30 days and c and a can do a piece of work in 36 days
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Answer:
Step-by-step explanation:
Let the Total Work be the LCM of the individual time taken.
LCM(8,24,607)=120parts
(A + B) = 8 days => (A + B) = 15 parts/day …. eqn (1)
(B + C) = 24 days => (B + C) = 5 parts/day …. eqn (2)
(C + A) = 607 days => (C + A) = 14 parts/day …. eqn (3)
Now, adding the three equations,
2(A + B + C) = 34 parts/day
=>(A + B + C) = 17 parts/day …. eqn (4)
Thus, from eqn (4) and eqn (1),
C = 2 parts/day
So, time taken by C =1202= 60 days
Thus, C alone takes 60 days (Answer)
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