Math, asked by deepaksoni5353, 1 year ago

A and b can do a piece of work in 24 days ,b and c can do apiece of work in 30 days and c and a can do a piece of work in 36 days

Answers

Answered by hrishihrishi200
0

Answer:

Step-by-step explanation:

Let the Total Work be the LCM of the individual time taken.

LCM(8,24,607)=120parts

(A + B) = 8 days => (A + B) = 15 parts/day …. eqn (1)

(B + C) = 24 days => (B + C) = 5 parts/day …. eqn (2)

(C + A) = 607 days => (C + A) = 14 parts/day …. eqn (3)

Now, adding the three equations,

2(A + B + C) = 34 parts/day

=>(A + B + C) = 17 parts/day …. eqn (4)

Thus, from eqn (4) and eqn (1),

C = 2 parts/day

So, time taken by C =1202= 60 days

Thus, C alone takes 60 days (Answer)

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